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java.util.InputMismatchException. Thrown by a Scanner to indicate that the token retrieved does not match the pattern for the expected type, or that the token is out of range for the expected type.Click to see full answer. Thereof, what does Java Util InputMismatchException mean?java. util. In this tutorial we will discuss about the InputMismatchException in Java. This exception is thrown by an instance of the Scanner class to indicate that a retrieved token does not match the pattern for the expected type, or that the retrieved token is out of range.Secondly, how do you handle type mismatch exception in Java? Handling input mismatch exception The only way to handle this exception is to make sure that you enter proper values while passing inputs. It is suggested to specify required values with complete details while reading data from user using scanner class. Moreover, how do I get Java Util InputMismatchException? If the user enters data that can’t be converted to an integer, however, the nextInt method throws an InputMismatchException. Then this exception is intercepted by the catch block — which disposes of the user’s incorrect input by calling the next method, as well as by displaying an error message.What is an arithmetic exception in Java?ArithmeticException : Thrown when an exceptional arithmetic condition has occurred. For example, an integer “divide by zero” throws an instance of this class. Moreover, most exceptions are constructed with a message to help you even further figure out what happened.

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